Help in Solving Square Root Problem

Introduction to solve square root problems:
The Square root problems of numbers are done when the number is multiplied through itself. In the same way for polynomial the square root is obtained when the polynomials are multiplied by it.
It is credible for solve together positive and negative numbers but when a negative number is taken out of root the value will become invented. There are two types of square problems such as ideal squares and non perfect square. It is simple to solve square root for perfect square.
Methods for Solving Square Root Problems:
The easiest method to define Square root problems in the method by using Prime Factorization:
(i) Write down the prime factorization of n from the given problems. Pair the factors such that primes in each pairs are equal.
(ii) Select one prime from every one couple and resolve multiplication of all such primes.
(iii) The multiplication obtained in (ii) is the square root of n problems.
These methods are used to solve the square root problems as easiest way.

Solve the square root of the following problems:
(a).√1600 = √2*√2*√5*√5*√4*√4.
According to the method, choose one prime from each pair
= 2*5*4.
= 40
So the perfect square root is 40.
(b).√900 = √3*√3*√5*√5*√2*√2.
According to the method, choose one prime from each pair,
= 3*5*2.
So the perfect square root is 30.
(c).√144 = √2*√2*√2*√2*√3*√3
According to the method, choose one prime from each pair,
= √4*√4*√3
=12.
So the solution is 12.
Non Perfect Squares:
Solve the square root of the following:
(a).√2352 = √2*√2*√2*√2*√3*√7*√7
According to the method, choose prime from each pair
= √4*√4*7*√3
According to the method, choose 4 as a prime from each pair
= 4*7*√3
=28*√3
So the square root of √2352 = 28*√3.
(b).√603 = √3*√3*√67
=3*√67
So, the square root of √603 = 3*√67.
(c).√9408 =√ 2*√2*√2*√2*√2*√2*√3*√7*√7
=2*2*2*7*√3.
=4*2*7*√3
=56*3.
So the square root of √9408= 56*3.